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5b^2-6b-104=0
a = 5; b = -6; c = -104;
Δ = b2-4ac
Δ = -62-4·5·(-104)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-46}{2*5}=\frac{-40}{10} =-4 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+46}{2*5}=\frac{52}{10} =5+1/5 $
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